What is the value of -3² +(-4+7)(2) A. -28 B. -3 C. 3 D. 15

Amanda made $154 for 11 hours of work. At the same rate, how many hours would she have to work to make $252?

goldenfox [79]

For this question you can say:
154/11 = 252/?
so ? is the hours she would work:
252*11/154 = 18 hours :)))
i hope this is helpful
have a nice day

3 0

3 years ago

Solve the equation for x, and enter your answer in the box below. 4x = 40

LenKa [72]

10x would be the answer

7 0

3 years ago

Read 2 more answers

Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int

Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula : $A=P(1+r)^t$

$A=5000(1+0.04)^3$

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{2})^{2 \times 3}$

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{4})^{4 \times 3}$

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{12})^{12 \times 3}$

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0

3 years ago

Ryan is X years old. Two times his age plus fifteen equals thirty-seven minus two. ( 2X + 15=37 - 2) Write an equation showing h

Misha Larkins [42]

Answer:

1) 10

2) 16

Step-by-step explanation:

1) 2x+15=37-2

2x+15=35

2x=35-15

2x=20

2 2

x=10

2)10x-8=9x+8

10x-9x=8+8

x=16

Hope this helps ❤

3 0

3 years ago

Given: is an angle bisector of ∠JMK Prove: m

astraxan [27]

Answer:

An angle bisector is a line passing through the vertex of the angle that cuts the angle into two equal smaller angles.

Given: MN is angle bisector,

then

$\angle JMN \cong \angle NMK$ ....... [1]

Congruent angles are two or more angles that have the same measure.

then;

by definition of congruent angles

[1]⇒ $m\angle JMN = m\angle NMK$ ......[2]

By the Angle addition postulates states that if M is in the interior of ∠JMK then,

$m\angle JMN+m\angle NMK =m\angle JMK$ ......[3]

Now, by substitution property ; substitute the equation [2] in [3] we get;

$m\angle JMN+m\angle JMN =m\angle JMK$ ......[4]

Like terms terms whose variables are the same

Combine like terms in equation [4] we get

$2 \cdot m\angle JMN=m\angle JMK$ ......[5]

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 2 to both sides in equation [5] , we get

$m\angle JMN= \frac{1}{2} m\angle JMK$

5 0

3 years ago

What is the value of -3² +(-4+7)(2)A. -28B. -3C. 3D. 15​

What is the value of -3² +(-4+7)(2)A. -28B. -3C. 3D. 15