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Gnoma [55]
2 years ago
8

Solve the equation for x, and enter your answer in the box below. 4x = 40

Mathematics
2 answers:
LenKa [72]2 years ago
7 0
10x would be the answer
faust18 [17]2 years ago
6 0

Answer:

10

Step-by-step explanation:

4x=40

40/4= 10

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855.77

Step-by-step explanation:

44500/52 equals 855.77

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Write a number sentence to represent the model. Explain how you determined the number sentence.
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The image attached shows an operation that can be represented with whole numbers, becuase there are positive and negative characters.

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Therefore, the model can be represented by the number -3, which is the whole because is the result of the operation that represent each type of element.

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the tens digit of a 2 digit number is twice the units digit. The sum of the digits is 12. Find the original number
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<span>2x + x = 12 
=> x =12/3 =4 
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3 years ago
Which equation can be used to find the area of trapezoid PQRT?
vladimir2022 [97]

Answer:

Area of a trapezoid is found with the formula, A=(a+b)/2 x h

Step-by-step explanation:

8 0
3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
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