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kow [346]
3 years ago
14

Related Rates

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

  1. 0.382 m/min
  2. 8 1/3 ft/s

Step-by-step explanation:

1. The rate of change of volume is ...

  V = πr^2h

  V' = πr^2h'

  h' = V'/(πr^2) = (3 m^3/min)/(π(5 m)^2) = 0.12/π m/min

  h' ≈ 0.382 m/min

__

2. In the attached, ∆PCM ~ ∆MXS, so we can write the proportion ...

  x/9 = s/15 . . . . where x = BX and s = BS in the diagram

Multiplying by 15 gives ...

  s = (15/9)x = (5/3)x

Then the rate of change is ...

  s' = (5/3)x' = (5/3)(5 ft/s)

  s' = 8 1/3 ft/s

The tip of the shadow is moving at 8 1/3 feet per second.

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Answer:

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$14 yr 10   $20 yr 11 etc. $25 year 12 etc.

We show yr 0 = 0  yr 1 = 8 and if 8 is the price we have a ratio start of 1:8 upon year 1. we then pinpoint the data what year was $16 and we know that yr 10 = $14 so yr 11 = $16.

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As the x y relationship coordinates can be shown here.

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and then change number of years to decades. To make a linear equation work we could change the rate upon the decade that shows a more stable rate of change to be of significance and easier to read.

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A linear function is a type of function of x and y proves a single line.

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And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

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Where "A" is the area of the walkway around the rectangular garden.

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The answer is:

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