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3 years ago

What is the name of the shape graphed by the function theta = pi/3

Mathematics

2 answers:

adelina 88 [10]3 years ago

5 0

Answer:

A line.

Step-by-step explanation:

This is a line passing through the origin and rising to the right. The angle betwee the line and the x axis = pi/3 radians.

barxatty [35]3 years ago

3 0

Answer:

C. Line.

Step-by-step explanation:

We are asked to find the name of shape that is graphed by the function $\theta =\frac{\pi}{3}$ .

We can see that the measure of theta is constant $\frac{\pi}{3}$ . This means that slope of function is also constant.

We know that slope of a straight line is always constant for all values in its domain.

Therefore, the shape of our given function is a line and option C is the correct choice.

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Simplify. 3.3÷(0.8−3)−0.5 Enter your answer in the box.

Veseljchak [2.6K]

Answer:

-2

Step-by-step explanation:

3.3÷(0.8−3)−0.5

First think of PEMDAS

So first do parenthese

(0.8-3)=-2.2

3.3÷-2.2-0.5

Now do division

3.3/-2.2=-1.5

and now subtraction

-1.5-0.5=-2

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3 years ago

Read 2 more answers

What transformation was made to ABC?

labwork [276]

Answer:

REFLECTION

Step-by-step explanation:

The triangle ABC was reflected over the x-axis to get triangle A'B'C'.

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3 years ago

Steven bought 3 mirrors. He paid a total of $264. Which equation can be used to find the amount he paid for each mirror?

musickatia [10]

Answer:

3÷264

Step-by-step explanation:

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3 years ago

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Alexandra [31]

Answer: 1. s*h 2. 20.4 hours

Step-by-step explanation: 1. s*h

2. 20.4 hours hope this helps.

7 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago