Answer: Choice A) 
This is the same as writing 14^3
===================================================
Explanation:
Since all the sides are 14 feet long, we can basically say length = width = height = 14.
Or put another way:
- length = 14
- width = 14
- height = 14
The volume of the cube is length*width*height = 14*14*14 = 14^3 = 2744 cubic feet.
-----------
The term 14^3 has a base of 14 and exponent of 3.
The base is what we multiply out while the exponent tells us how many copies of the base to multiply. In this problem, we have 3 copies of 14 being multiplied. So that's why 14^3 = 14*14*14
If you were to say something like 3^14, then you would have 14 copies of 3 multiplied out, which is a much larger value. So we'll cross choice B off the list.
Choice C isn't correct either since again we're using exponents and not multiplication to tie together the 14 and 3.
Choice D would be correct if your teacher wanted it in expanded form, instead of exponent form.
If it’s asking if it’s true of false it’s false
Because 5/11x6/7 =30/77
Add the balance and allotment:
22.90 + 50.00 = 72.90
This is how much she can actually spend.
She spent 85.50.
Subtract the two:
85.50 - 72.90 = 12.60
Since she spent more than she actually could be balance would be a negative number.
The balance would be - $12.60
For this case we have to:
x: Let the variable representing the unknown number
We algebraically rewrite the given expression:
Twice a number plus 10, is represented as:
Three times that number less 4. is represented as:
Thus, the complete expression is:
Subtracting 3x from both sides of the inequality:
Subtracting 10 from both sides of the inequality:
Equal signs are added and the same sign is placed:
We multiply by -1 on both sides, taking into account that the sense of inequality changes:
The solution is given by all values of "x" less than 14.
Answer:
Answer:
139,999
Step-by-step explanation:
If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999
