Answer:
The 64 ounce jug of milk costs $0.010 more per ounce than the 128 ounce jug of milk/
Step-by-step explanation:
3.20/128=$0.025 per ounce jug of milk
2.24/64=$0.035 per ounce jug of milk
0.035 - 0.025 = .010
The resulting equation will represent a line whose slope is 1/2 times the slope of the line
<h3>How to determine the slope of the new line?</h3>
The equation of the line is given as:
y = 3x/a + 5
The constant a is a positive constant.
So, when the value of a in the equation is doubled, we have:
y = 3x/2a + 5
A linear equation is represented as
y = mx + b
Where m represents the slope.
So, we have:
m1 = 3/a
m2 = 3/2a
Substitute m1 = 3/a in m2 = 3/2a
m2 = 1/2 * m1
Hence, the resulting equation will represent a line whose slope is 1/2 times the slope of the line
Read more about linear equation at:
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Answer: 0
Step-by-step explanation:
Since m is with x, you don't need to care about y
We would get 2x - 6x + 4x = mx
0x = mx
m is 0
17/30 feet
Explanation:
Blue fish: 2/15 feet long
Orange fish: 7/10 feet long
Subtract the orange fish’s length by the blue fish’s:
7/10 - 2/15
Find LCD- 30
Multiply both denominators of each fraction by a number that makes both 30 (whatever that number is multiply that also to both nunerators):
7 • 3 / 10 • 3 = 21/30
2 • 2 / 15 • 2 = 4/30
SUBTRACT:
21/30 - 4/30 = 17/30
FINAL ANSWER: the orange fish is 17/30 feet longer than the blue fish.
BRAINLIEST PLEASE! Have a nice day
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.

Substitute (3) into (2)

Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)

Set up a quadratic equation

Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°