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forsale [732]
3 years ago
14

Find the gradients of line a and b

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

Gradient of A: 2

Gradient of B: -1

Step-by-step explanation:

Gradient = change in y/change in x

✔️Gradient of A using two points on line A, (2, 5) and (0, 1):

Gradient = (1 - 5)/(0 - 2) = -4/-2

Simplify

Gradient of A = 2

✔️Gradient of B using two points on line B, (0, 5) and (5, 0):

Gradient = (0 - 5)/(5 - 0) = -5/5

Simplify

Gradient of B = -1

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What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

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<em>The result can be shown in both exact and decimal forms. </em>

<em>Exact Form: </em>

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<em>Decimal Form: </em>

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Thanks,

<em>Deku ❤</em>

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