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Marianna [84]
3 years ago
15

Solve for x: 4x+2=1/2x+17

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
THE STEPS AND ANSWER IS IN THE PICTURE

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6x-3y =15<br><br><br> (System of Equations)
Vadim26 [7]

Answer:

x= 5/2 + y/2

Step-by-step explanation:

So yeah... that's the answer

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3 years ago
A rectangular swimming pool is 40 feet long and 20 feet wide. The pool is bordered by square tiles that are x feet in length sur
olga2289 [7]

Answer:

(40 + 2x)feet

Step-by-step explanation:

see attachment for the figure.

Let 'L' represents the length of the rectangular swimming pool i.e 40ft wide.

and pool is bordered by square tiles that are x feet in length surrounding the pool

therefore,

In order to find the longest side of the pool and the tile border, take the sum of  length of the swimming pool i.e 40 adding two times the wide of the square tiles

(40+2x)feet.

6 0
4 years ago
A gold chain with an original price of $150 is on sale for $87 what is the percent of the discount
kap26 [50]

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i believe its 58%

Step-by-step explanation:

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2 years ago
Solve the Antiderivative.​
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Ln ( | Sec (e^x + π) + tan ( e^x +π ) | )
4 0
3 years ago
Read 2 more answers
Radon is a gas produced when radium decays, and it can enter homes where it can be a health threat. Among 180 homes in Hyde Park
mylen [45]

Answer:

We are given that Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels. Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

Claim : the two towns have different rates of unsafe radon levels.

Let p_1 and p_2be the rates of unsafe radon levels of Hyde Park and LaGrange respectively .

H_0:p_1=p_2\\H_a:p_1\neq p_2

Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels

So, n_1=180, y_1=25

Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

So, n_2=230, y_2=50

We will use Comparing Two Proportions

\widehat{p_1}=\frac{y_1}{n_1}

\widehat{p_1}=\frac{25}{180}

\widehat{p_1}=0.1388

\widehat{p_2}=\frac{y_2}{n_2}

\widehat{p_2}=\frac{50}{230}

\widehat{p_2}=0.217

\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{25+50}{180+230}=0.1829

Formula of test statistic :\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}

Substitute the values  

test statistic :\frac{0.138-0.217}{\sqrt{0.1829(1-0.1829)(\frac{1}{180}+\frac{1}{230})}}

test statistic :  −2.053

Refer the z table for p value

p value = 0.0202

α= 0.05

Since p value < α

So, we reject the null hypothesis that the two towns have same rates of unsafe radon levels.

So, Claim is true.

3 0
4 years ago
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