Lines are in the form y=mx+b, where m is the slope and b is the y-intercept. This line is thus y=9/4x-14, so C is correct. Multiplying by four, we get 4y=9x-56. Adding 56 and subtracting 4y, we see that 9x-4y=56, and multiplying by -1, we get 4y-9x=-56, so A is also correct. At this point, it is clear that B and D are incorrect, so A and C only are correct.
Answer:
X=10.5
Step-by-step explanation:
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!
Answer:
See below.
Step-by-step explanation:
a.
O is the origin, so its abscissa is 0. O: 0
The only point 4 units from O is A, so A: 4
Point C has a positive abscissa like A.
Points B and C have opposite abscissas. The only opposites are -3 and 3, but C is positive, and B is negative.
B: -3
C: 3
D: -4.5
E: -6
M = (4 + (-6))/2 = -1. M: -1
b.
OB = |0 - (-3)| = |3| = 3
DA = |-4.5 - 4| = |-8.5| = 8.5
The width is 8. The length is 10 so 10+10 equals 20. You subtract 20 from 36 you get 16. 16/2 is 8. If you add 8+8+10+10 you get 36.
