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guajiro [1.7K]
2 years ago
11

Hellohello, if you able to help me then please do. (:

Mathematics
1 answer:
PolarNik [594]2 years ago
6 0

Answer:

Step-by-step explanation:

it will always be true as long as it is adittion the r is the unknown number just add 15 plus what equals 25

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Please help me and answer both? tysm and enjoy your day! hope this helps!
IceJOKER [234]
The answer is C and b
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2 years ago
Find the volume of each sphere to the nearest hundredth?​
Alenkinab [10]

Answer:

Can i have a diagram please

Step-by-step explanation:

4 0
3 years ago
Robert's dog is 4 years older than Karen's cat. In 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. How
mylen [45]

Answer:

5.5 years old.

Step-by-step explanation:

Let D represent present age of Robert's dog and C represent present age of Karen's cat.

We have been given that Robert's dog is 4 years older than Karen's cat. We can represent this information in an equation as:

D=C+4...(1)

We are also told that in 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. After 3 years age of dog and cat would be D+3 and C+3 respectively.

We can represent this information in an equation as:

D+3+C+3=13...(2)

From equation (1), we will get:

C=D-4

Upon substituting this value in equation (2), we will get:

D+3+D-4+3=13

Combine like terms:

2D+2=13

2D+2-2=13-2

2D=11

\frac{2D}{2}=\frac{11}{2}

D=5.5

Therefore, Robert's dog is 5.5 years old right now.

3 0
3 years ago
Find the value for x to the third decimal place: In x=5
mixas84 [53]

\ln x=5\implies x=e^5\approx0.6738\cdot10^{-2}.

Hope this helps.

8 0
2 years ago
3. These 3 congruent square pyramids can be assembled into a cube with side length 1
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Answer:

Wow Ashley I see you keep looking for the answers.

Step-by-step explanation:

This is the second time I have seen you looking for the answers on the internet, I am now thinking about giving you a zero for this week's homework. Please refrain from copying because I do not want to give you a bad score.

3 0
2 years ago
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