B: 4/5
All you need to do is put the first number over the second and simplify. In this case you don't need to simplify because it is in its simplest form
<u>Answer-</u>
<em>The area of QRS is </em><em>238.7</em><em> sq units.</em>
<u>Solution-</u>
According to properties of supplementary angles,
![m\angle R+124=180\\\\m\angle Q+132=180](https://tex.z-dn.net/?f=m%5Cangle%20R%2B124%3D180%5C%5C%5C%5Cm%5Cangle%20Q%2B132%3D180)
So,
![\Rightarrow m\angle R=180-124=56,\ m\angle Q=180-132=48](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20R%3D180-124%3D56%2C%5C%20m%5Cangle%20Q%3D180-132%3D48)
As the sum of measurement of all the angles in a triangle is 180, so
![\Rightarrow m\angle S+m\angle R+m\angle Q=180](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%2Bm%5Cangle%20R%2Bm%5Cangle%20Q%3D180)
![\Rightarrow m\angle S=180-m\angle R-m\angle Q](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%3D180-m%5Cangle%20R-m%5Cangle%20Q)
![\Rightarrow m\angle S=180-56-48=76](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%3D180-56-48%3D76)
Then the area of the triangle will be,
![\text{Area}=\dfrac{1}{2}qr\sin S](https://tex.z-dn.net/?f=%5Ctext%7BArea%7D%3D%5Cdfrac%7B1%7D%7B2%7Dqr%5Csin%20S)
![=\dfrac{1}{2}\times 21\times 23.43\times \sin 76](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2021%5Ctimes%2023.43%5Ctimes%20%5Csin%2076)
![=238.7\text{sq.units}](https://tex.z-dn.net/?f=%3D238.7%5Ctext%7Bsq.units%7D)
Answer:
Step-by-step explanation:
Both angles are supplementary (they add up to 180°)
This means that (10x) + (6x - 12°) = 180°
(10x) + (6x - 12°) = 180°
10x + 6x - 12° = 180°
16x - 12° = 180°
16x = 192°
x = 12°
Hope this helps!
Answer:
The first one shows 25%
In the 1st modal, a whole is divided into 4 and 1 of the 4 is selected or highlighted
And as the whole rectangle is 100% and being divided into four its becomes 100/4% and when we solve we get 100/4=25
And thus its the first modal that shows 25%
In the second case its divide into 3 boxes so.. 100/3% and when we solve we get 33.3333333.......and this is not what we want
THEREFORE, THE CORRECT ANSWER IS 1ST MODAL
Step OneFor convenience f(x) = y
y = -(1/2) sqrt(x + 3) Interchange x and y
x = -(1/2) sqrt(y + 3) Multiply both sides by -2
(-2x) = sqrt(y + 3) Square both sides
4x^2 = y + 3 Subtract 3 from both sides
4x^2 -3 = y
f-1(x) = 4x^2 - 3
GraphsThe original graph is in blue
The inverse is red.
Green Line y = x : explained below.
CommentInverses have a very strange property. It acts as a check.
If you perform the following operation
f-1(f(x)) you are left with x
In this case f-1[-1/2 sqrt(x + 3)]= 4(-1/2 * sqrt(x + 3))^2 - 3
f-1 (-1/2sqrt(x+3)) = 4 (1/4 (x+3) - 3
f-1(-1/2sqrt(x + 3)) = x+ 3 - 3 = x
I've included this because I think you have to put the same restriction on f-1(x) as you do on f(x) which is that for f(x) x ≥ -3
This last assertion could be incorrect, but I don't think so.
The answer is f-1(x) = 4x^2 - 3 <<<<<
answer first box and
x≥-3 for the second box. <<<<<<
answer for the second box.Let me know if these are correct. I'm not sure about the restrictions.