Replacing point A (-1, 1) on the left side of the equation gives
((-1) - 3)^2 + (1)^2 = 17
which is less than 49, so the point is on the interior of the circle
Replacing point B (10, 0) on the left side of the equation gives
((10) - 3)^2 + (0)^2 = 49
So the point is on the circumference of the circle
Replacing point B (4, -8) on the left side of the equation gives
((4) - 3)^2 + (-8)^2 = 65
which is greater than 49, so the point is on the exterior of the circle