Answer: air pressure
Explanation:
Air masses tend to flow from areas of high air pressure to areas of low air pressure. Thus, winds blow away from high-pressure areas; wind blows towards low-pressure areas. Air masses also move vertically.
The change in partial pressure from the alveoli (high concentration) to
the capillaries (low concentration) drives the oxygen into the tissue
and the carbon dioxide into the blood (high concentration) from the
tissues (low concentration), which is then returned to the lungs and
exhaled.
Once in the blood of the capillaries, the O2 binds to the
hemoglobin in red blood cells which carry it to the tissues where it
dissociates to enter the cells of the tissues.
The lungs never fully
deflate, so air that is inhaled mixes with the residual air left from
the previous respiration, resulting in a lower partial pressure of
oxygen within the alveoli.
Answer:
7.8 moles are needed.
Explanation:
Given data:
Mass of oxygen produced = 125 g
Number of moles of mercury oxide needed = ?
Solution:
Chemical equation;
2HgO → 2Hg + O₂
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 125 g/ 32 g/mol
Number of moles = 3.9 mol
Now we will compare the moles of oxygen with mercury oxide.
O₂ : HgO
1 : 2
3.9 : 2×3.9 = 7.8 mol
The answer is C hopefully my answer was helpful?
