How do I find z,x, and y in a triangle with three angles of 64 degrees, 28 degrees, and 39 degrees
1 answer:
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We can write
cos(t) = x/6
so
y = 5(±√(1 -(x/6)^2)*x/6
Then
y' = (±5/6)*(√(1 -(x/6)^2) + x/(2√(1 -(x/6)^2)*(-2(x/6))
The limit as x → 0 is ±5/6
The equations of the two tangents are
y = (5/6)x
y = (-5/6)x
cos(t) = x/6
so
y = 5(±√(1 -(x/6)^2)*x/6
Then
y' = (±5/6)*(√(1 -(x/6)^2) + x/(2√(1 -(x/6)^2)*(-2(x/6))
The limit as x → 0 is ±5/6
The equations of the two tangents are
y = (5/6)x
y = (-5/6)x