By applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
<em><u>Given:</u></em>

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB



<u>b. </u><u>Find the length of </u><u>AB:</u>

AC = 6.15 cm
To find BC, use AC/BC = EC/DC.




Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
Learn more here:
brainly.com/question/14327552
Answer:
10x^2 y(2x + 3y)
Step-by-step explanation:
20x^3 y + 30x^2 y^2.
Factor 10x^2y out of 20x^3y.
10x^2 y (2x) + 30x^2 y^2
Factor 10x^2y out of 30x^2y^2.
10x^2 y (2x) + 10x^2 y (3y)
Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).
10x^2 y(2x + 3y)
you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option