2(x-6y+4z=2)
2x+4y-8z=16
2x-12y+8z=4
2x+4y-8z=16
4x-8y=20
x-2y=5
4x-8y=20
-4x+8y=-20
infinite many solutions
First, ensure that both sides are single fractions:

By cross multiply, we mean:
1. multiplying the numerator of the left hand side with the denominator of the right hand side.
2.multiplying the numerator of the right hand side with the denominator of the left hand side.
That is ..
a x d = c x b
It is rational and equal to 0. square root of 28 simplifies to 2 root 7, because you can take out the 4 and leave the 7 under the radical. because sq rt of 28 is 2 root 7, it's the same as the first term so it equals 0
Answer:
I hate to do and take the points but so we just got to find the angles?
A1=2
a2=-8
a3=32
a4=-128
a2/a1=(-8)/2→a2/a1=-4
a3/a2=32/(-8)→a3/a2=-4
a4/a3=(-128)/32→a4/a3=-4
a2/a1=a3/a2=a4/a3=r=-4
an=a1*r^(n-1)
an=2*(-4)^(n-1)
The explicit rule for the nth term of the given sequence is an=2*(-4)^(n-1)