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Vika [28.1K]
3 years ago
11

I need this quick please

Mathematics
2 answers:
zysi [14]3 years ago
7 0
I think your answer will be either b or c i think if im wrong im sorry
Nady [450]3 years ago
4 0
The answer is B, 1.4
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Solve log (4x+5)=2. Round to the nearest thousandth if necessary.
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10%5E2+=+4x+%2B+5
100+=+4x+%2B+5
4x+=+95
x+=+23.75
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Andrea ran 400 meters in gym class How many cm. did she run
aliya0001 [1]
1 m = 100 cm

Multiply:

100 * 400 = 40000

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Which of the following are one-dimensional and have infinite length?
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Out of the choices, the entities with only one dimension and have infinite length are the line and ray. The line extends to both sides while the ray is restricted by an endpoint on one side but can extend infinitely to the other side. The answers are therefore letter D and F. 
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Find the distance between the two points rounding to the nearest tenth (if necessary).
Sergio [31]

Answer:

6.7 units

Step-by-step explanation:

The distance between two points can be found using the formula below:

\boxed{{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2}  } }}

Thus, distance between (-1, 2) and (2, -4)

=  \sqrt{( - 4 - 2)^{2} +  { [2-(-1) ]}^{2}  }

=  \sqrt{ {( - 6)}^{2}  +   {(2 + 1)}^{2} }

=  \sqrt{36 + 9}

=  \sqrt{45}

= 6.7 units (nearest tenth)

Additional:

For a similar question on distance between points, do check out the following!

  • brainly.com/question/23274198

6 0
1 year ago
According to a report from the Center for Studying Health System Change, 20% of Americans delay or go without medical care becau
Svet_ta [14]

Answer:

The probability no one delays or goes without medical care is 0.168;

The probability only one person delays or goes without medical care is 0.336.

Step-by-step explanation:

This problem can be modeled with a binomial random variable, with sample size n=8 and probability of success p=0.2.

The probability that <em>exactly </em>k Americans delay or go without medical care because of concerns about cost within the sample of eight individuals can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.2^{k} 0.8^{8-k}\\\\\\

The probability no one delays or goes without medical care (x=0) is:

P(x=0) = \dbinom{8}{0} p^{0}(1-p)^{8}=1*1*0.168=0.168\\\\\\

The probability only one person delays or goes without medical care (x=1) is

P(x=1) = \dbinom{8}{1} p^{1}(1-p)^{7}=8*0.2*0.21=0.336\\\\\\

4 0
3 years ago
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