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Marysya12 [62]
3 years ago
12

Write an equation of the line that passes through the point (-6,-5) with slope 6

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

y + 5 = 6(x + 6)

Step-by-step explanation:

Apply the point-slope formula y - k = m(x - h):

y + 5 = 6(x + 6)

lisabon 2012 [21]3 years ago
5 0

Answer:

y=6x-31

Step-by-step explanation:

We know that the line passes through the point (-6,-5) so we can substitute the x and y coordinates into the equation of a line y=mx+b, where y and x are the respective coordinates, m is slope, and b is the y-intercept. We can also plug in 6 to the equation for slope.

y=mx+b

-5=(6)(-6)+b

Solve for b, the y-intercept

b=-36+5=-31

Therefore, the equation of the line is: y=6x-31

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Hunter-Best [27]

Answer: -36a^6+32a^4

Step-by-step explanation:

4 0
2 years ago
Help me please with this math question
erica [24]
The slope is negative. the slope is calculated by using “rise over run”. in the problem, you go down 2 and over 1. so your answer is -2/1 or -2
7 0
3 years ago
Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find
Dennis_Churaev [7]

Answer:

  1. \$30,460
  2. \$30,497
  3. \$30,522
  4. \$30,535

Step-by-step explanation:

We know that,

A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}

=25000\left (1+0.025\right )^{8}

=25000\left (1.025\right )^{8}

=\$30,460

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}

=25000\left (1+0.0125\right )^{16}

=25000\left (1.0125\right )^{8}

=\$30,497

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}

A=25000\left (1+\dfrac{0.05}{12}\right )^{48}

=\$30,522

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

A= Pe^{rt}

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

A= 25000e^{0.05\times 4}=\$30,535

It can be observed that, the frequent we compound the amount, the more we get.

7 0
3 years ago
Below are two parallel lines with a third line intersecting them.
Brums [2.3K]

Answer:

  x° = 131°

Step-by-step explanation:

The two marked angles are on opposite sides of the transversal, so they are called "alternate" angles. They are both between the parallel lines, so they are called "interior" angles.

In this geometry, <em>alternate interior</em> angles are congruent. They have the same measure. x° = 131°.

5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Aliun [14]

Answer:

i think its 24

Step-by-step explanation:

2=2

8 0
2 years ago
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