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aev [14]
4 years ago
15

What are the 2 numbers when 30 is the product and -11 is the sum

Mathematics
1 answer:
MArishka [77]4 years ago
6 0

the answer would be -5 and -6.

-5 + -6 = -11 and -5 * -6 = 30 because when multiplying, you cancel out the negative sign when you've got an even amount of negatives.

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How do you find the equation of a line with Guassian elimination given two points?
Paraphin [41]

Answer:

  The solution is similar to the 2-point form of the equation for a line:

  y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)

Step-by-step explanation:

Using the two points, write two equations in the unknowns of the equation of the line.

For example, you can use the equation ...

  y = mx + b

Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:

  b + (x1)m = (y1)

  b + (x2)m = (y2)

The corresponding augmented matrix for this system is ...

  \left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]

____

The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.

  0 + (x2 -x1)m = (y2 -y1)

Dividing by the value in row 2 column 2 gives you the value of m:

  m = (y2 -y1)/(x2 -x1)

This value can be substituted into either equation to find the value of b.

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7 0
3 years ago
Solve the following inequality: 3-5x-x^2&gt;=0
Dennis_Churaev [7]

Answer:

-5/2+-1/2√37≤x≤-5/2+1/2√37

Step-by-step explanation:

Step 1: Find the critical points

-x^2-5x+3=0

For this equation: a=-1, b=-5, c=3

−1x^2+−5x+3=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(−1)(3)/2(-1)

x=5±√37 /−2

x=-5/2+1/2√37

Step 2: Check intervals in between critical points

x≤-5/2+1/2 √37 (Doesn't work in original inequality)

-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)

x≥-5/2+1/2 √37 (Doesn't work in original inequality)

5 0
3 years ago
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