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saveliy_v [14]
2 years ago
10

Can someone help me out

Mathematics
1 answer:
seraphim [82]2 years ago
5 0
A is addition
b is subtraction
c is division
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Hank has large of trail mid weighs 7.8 pounds. He uses the mix in the large bag to make bags each containing 0.6 pounds of mix.
KonstantinChe [14]

Answer:

hi... bye... figgure it out yourself

Step-by-step explanation:

qwertyuiopasdfghjklzxcvbnmqwertyuiopasdfghjklzxcvbnm

6 0
3 years ago
Write an equation for the line that is parallel to the given line and that passes through the given point.
Rasek [7]
Parallel to y = 3/4x - 9 and passes through (-8, -18)

Identify the slope : our slope is 3/4

Remember that parallel equations have the same slope, so both slopes are 3/4

Now, we have to find the y-intercept. Simply plug everything into the slope intercept form equation.

y = mx + b

(-18) = (3/4)(-8) + b

Simplify.

-18 = -6 + b

Add 6 to both sides.

-18 + 6 = b

Therefore, our y-intercept is -12.

Now plug everything into the slope intercept form.

y = mx + b

y = 3/4x - 12

~Hope I helped!~
4 0
3 years ago
Find the particular solution to y'=2sin(x) given the general solution is y=C-2cos(x) and the initial condition y(pi/3)=1
mezya [45]

ANSWER

The particular solution is:

y=2-2 \cos(x)

EXPLANATION

The given Ordinary Differential Equation is

y'=2 \sin(x)

The general solution to this Differential equation is:

y=C-2 \cos(x)

To find the particular solution, we need to apply the initial conditions (ICs)

y( \frac{\pi}{3} ) = 1

This implies that;

C-2 \cos( \frac{\pi}{3} ) = 1

C-2( \frac{1}{2} )= 1

C-1= 1

C= 1 + 1 = 2

Hence the particular solution is

y=2-2 \cos(x)

4 0
3 years ago
Please help!! this is due TODAY!
Rzqust [24]
C I’m pretty sure that’s what is it
7 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
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