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Ostrovityanka [42]
2 years ago
12

Giovanna owns a farm. She is going to randomly select one animal to present at the state fair. She has 6 pigs, 7 chickens, and 1

0 cows.
What is P(chicken)

It's not 7 it wants the percent.
Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

0.3043 or 30.43%

Step-by-step explanation:

I think what you are asking is what is the chance of her choosing a chicken?  if so, just take the number of chicken divided by the total number of animals.

7 divided by 23 = 0.3043

you could also take the chance of choosing any animal ( 1 out of 23 ) and multiply by how many chickens there are too, but that is a bit more messy with the decimals.

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Which point would be a solution to the system of linear inequalities ?
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(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

-6\geq -\frac{5}{2}(-6)+5

-6\geq 20----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0
3 years ago
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