Pre-Algebra Examples .The perimeter of a rectangle is equal to the sum of all sides of the rectangle. Substitute the values of the length l=2 l = 2 and width .
See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
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As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS=======OR=======So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS
Answer:
$10.80
Step-by-step explanation:
$60.00 x 0.18 = $10.80
x = 95°
the polygon has 5 sides so you do n - 2 which is (number of sides - 2) this gives us 3. now multiply 3 times 180, this gives us 540. now add up all the sides that you know, 104, 117, 100, 124, this is 445 now subract 445 from 540 and that is what gives us 95°
Step-by-step explanation:
1.8×10 to the power of 8
8.0×10 to the power of 6
1.2 ×10 to the power of 6
2.4×10 to the power of 2