Schizocoelic development
The coelom is a fluid-filled body cavity, where the internal organs are suspended in. It is the cavity between the wall of the body and the digestive tract.
In the schizocoelic development of the embryo, the coelom, called the schizocoel, develops as a split in the mesoderm. The outer layer of the mesoderm attaches with the ectoderm to form a body's musculature, while the inner layer attaches with the endoderm to form the wall of the digestive tract.
This type of development is commonly found in annelids, arthropods, and mollusks.
Answer:
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Explanation:
Answer:
- Organism A is most likely a herbivore
- Organism B is most likey a carnivore
Explanation:
Based on feeding habit, organisms, usually animals, can be classified into three categories namely: herbivores, carnivores and omnivores.
- Herbivores are those organisms that feed on vegetative matter i.e. plants while carnivores are those organisms that feed on flesh of other animals or organisms. Based on what they feed on, herbivores are adapted to possess blunt teeth (for chewing) like Organism A in this question while carnivores are adapted to possess sharp teeth (for tearing flesh) like Organism B.
Based on the above explanation, organism A is most likely a HERBIVORE while organisms B is most likely a CARNIVORE.
- Another notable point of difference between herbivores and carnivores, which is likely to differentiate organism A and B as well, is that herbivores possess digestive enzyme- amylase in their saliva while carnivores do not. Herbivores need AMYLASE to break down complex carbohydrate (starch) in the plants they feed on.
organelles
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q=0,78
To calculate the frequency of the allele we use the Hardy-Weinberg equation. The Hardy-Weinberg equation is used to calculate the genetic variation of a population at equilibrium. If the alleles are A and a, p is the frequency of the allele A and q is the frequency of the allele a. Hardy-Weinberg equation for alleles A and a:
p² + 2pq + q² = 1
p² is the frequency of the homozygous genotype AA, 2pq is the frequency of the heterozygous genotype Aa and q² is the frequency of the homozygous genotype aa.
p²+2pq+q²=(p+q)²=1
p+q=1
<span>If p=0,22 q=1-0,22=0,78</span>
