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Helen [10]
3 years ago
6

What is the simplified form of 3a^4b^-2c^3

Mathematics
1 answer:
adell [148]3 years ago
8 0
It would be 3a^4c^3/b^2
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What you have to do is add up the amount of total grade scores. 76+99+86+x. You get 261+x. you have to get 99% or higher

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One angle is 25 less than four times it's supplement. What is the measure of both angles?
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Let the first angle be x and the second be y.

Supplementary angles add up to 180, so:
x + y = 180

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x = 4y - 25

Substituting into the first equation:
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<em>1</em><em>/</em><em>2</em><em> </em><em>base</em><em>*</em><em>height</em>

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3 years ago
there are approximately 4021/4 meters around a typical running track sandra has challenged herself to run 10 maps a day for 5 da
Lostsunrise [7]

Total distance of a typical running track  = 402 \frac{1}{4} meters.

Let us convert it into impoerper fraction first, we get

\frac{402\times4+1}{4}=\frac{1609}{4}meters.

Total number of maps in a day = 10 maps.

Number of days of running = 5 days.

Total number of maps of 5 days = 10 × 5 = 50 maps.

Total number of meters in 50 maps = 50\times\frac{1609}{4}=\frac{80450}{4}=20112\frac{1}{2}\ meters..

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4 years ago
What function do you know from calculus is such that its first derivative is itself?The above function is a solution of which of
Nataliya [291]

Answer:

a.  y= e raise to power y

c. y = e^ky

Step-by-step explanation:

The first derivative is obtained by making the exponent the coefficient and decreasing the exponent by 1 . In simple form the first derivative of

x³ would be 2x³-² or 2x².

But when we take the first derivative of  y= e raise to power y

we get y= e raise to power y. This is because the derivative of e raise to power is equal to e raise to power y.

On simplification

y= e^y

Applying ln to both sides

lny= ln (e^y)

lny= 1

Now we can apply chain rule to solve ln of y

lny = 1

1/y y~= 1

y`= y

therefore

derivative of e^y = e^y

The chain rule states that when we have a function having one variable and one exponent then we first take the derivative w.r.t to the exponent and then with respect to the function.

Similarly when we take the first derivative of  y= e raise to power ky

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On simplification

y= k e^ky

Applying ln to both sides

lny=k ln (e^y)

lny=ln k

Now we can apply chain rule to solve ln of y ( ln of constant would give a constant)

lny = ln k

1/y y~= k

y`=k y

therefore

derivative of e^ky = ke^ky

3 0
3 years ago
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