All categories

3 years ago

A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?

Mathematics

1 answer:

Ugo [173]3 years ago

3 0

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

$Density = \frac{Mass}{Volume}$

$\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3$

The density of the gold sample is 19.3g/cm³

Learn more here: brainly.com/question/17780219

You might be interested in

Kim is buying an equal number of ounces of gummy bears and chocolate drops for her friends. Kim has $10 to spend at the store. I

katrin [286]

Answer:

128 oz

Step-by-step explanation:

Add $0.50 and $0.75 till you get 10

Count the times you added them, which is 8 times (equal)

Then 8 to ounces is 128 oz

Bye, have a great Day/Night :)

4 0

3 years ago

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 704t

Sever21 [200]

At least 20 charactersssssssssssss

7 0

4 years ago

Place the indicated product in the proper location on the grid.

marishachu [46]

Answer:

See explanation

Step-by-step explanation:

$(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3=a^3+b^3$

$(1-7x)(1+9x)=1+9x-7x-63x^2=-63x^2+2x+1$

$(x+y+3)(x+y-4)=x^2+xy-4x+xy+y^2-4y+3x+3y-12=x^2+2xy+y^2-x-y-12$

$(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3$

$(m^3n+8)(m^3n-5)=(m^3n)^2-5m^3n+8m^3n-40=m^6n^2+3m^3n-40$

$(4-(3c-1))(6-(3c-1))=(4-3c+1)(6-3c+1)=(5-3c)(7-3c)=35-15c-21c+9c^2=9c^2-36c+35$

$(ab-9)(ab+8)=(ab)^2+8ab-9ab-72=a^2b^2-ab-72$

$(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab$

$(a+3)(a-2)=a^2-2a+3a-6=a^2+a-6$

10.

$(3m^3-y)(3m^3-y)=(3m^3)^2-3m^3y-3m^3y+y^2=9m^6-6m^3y+y^2$

11.

$(2x-3y)(4x-y)=8x^2-2xy-12xy+3y^2=8x^2-14xy+3y^2$

12.

$(x^2+2x-1)(x^2+2x+5)=x^4+2x^3+5x^2+2x^3+4x^2+10x-x^2-2x-5=x^4+4x^3+8x^2+8x-5$

13.

$(4x-3y+5)(x+2y-3)=4x^2+8xy-12x-3xy-6y^2+9y+5x+10y-15=4x^2+5xy-6y^2-7x+19y-15$

8 0

4 years ago

Find a quadratic function with the given x-values as the only two REAL zeros. x=-2 and x=8. Please show work! Will mark Brainlie

posledela

f(x) = (x- zero) * (x -zero)

f(x) = (x--2) (x-8)

f(x) = (x+2) (x-8)

if you need it multiplied out

f(x) = x^2 +2x -8x-16

f(x) = x^2 -6x-16

3 0

3 years ago

Can you name the trigonometric expression that is equivalent to the following expression 1/secant of x?

Arlecino [84]

The answer to your question is: Yes, I can.

You haven't asked for the trigonometric expression, but here it is anyway:

The <u>cosine</u> function is the reciprocal of the secant function.

8 0

3 years ago