One example would be x to the power of 1/3
which we would write as x^(1/3) for shorthand
It converts to "cube root of x".
----------------
The general rule is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
if the font is too small, then the formula reads x^(1/n) is equal to square root x, with a small little n just above and to the left of the square root. This is known as the nth root of x.
Based on that general formula, we can say something like
![x^{1/4} = \sqrt[4]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%7D)
(x to the 1/4th power is equal to fourth root of x)
note: you can replace x with any algebraic expression you want
Answer:

Step-by-step explanation:
Take out 4:
4(x^2-8x)-12
=4(x^2-8x+16-16)-12
=4(x^2-8x+16)-64-12
=4(x^2-4)^2 - 76
=
Answer: 15
Step-by-step explanation:
(r+1)th term of
is given by:-

For
, n= 6

![=\ \dfrac{6!}{4!2!}a^4b^2\ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{6\times5\times4!}{4!\times2}a^4b^2\\\\=3\times5a^4b^2\\\\ =15a^4b^2](https://tex.z-dn.net/?f=%3D%5C%20%5Cdfrac%7B6%21%7D%7B4%212%21%7Da%5E4b%5E2%5C%20%5C%20%5C%20%5B%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B6%5Ctimes5%5Ctimes4%21%7D%7B4%21%5Ctimes2%7Da%5E4b%5E2%5C%5C%5C%5C%3D3%5Ctimes5a%5E4b%5E2%5C%5C%5C%5C%20%3D15a%5E4b%5E2)
Hence, the coefficient of the third term in the binomial expansion of
is 15.
Answer:
Find the inverse f-1(x) for the given function f(x)=2x-5
Step-by-step explanation:
To find the inverse, interchange the variables and solve for y
f
^−
1
(
x
)
=
x
/2
+
5/2