2 years ago

What’s the answer? 12-3y=30x+6

Mathematics

1 answer:

svet-max [94.6K]2 years ago

6 0

Answer:

The answer is y=−10x+2

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Write an appropriate direct variation equation if y = 18 when x = 2

Sergeu [11.5K]

Answer:

$y=9x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem we have

y=18 when x=2

Find the value of the constant of proportionality k

$k=\frac{y}{x}$ ----> $k=\frac{18}{2}=9$

therefore

The equation is equal to

$y=9x$

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3 years ago

Which expression is equivalent to -9x-1y-9/-15x5y-3?

FrozenT [24]

Answer: -9x-1y-9/

Step-by-step explanation:

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2 years ago

What is the first quartile of the data displayed in this box-and-whisker plot? A)49 B)41 C)37 D)35

fiasKO [112]

C. 37
It is the lower quartile marked on the box-and-whisker plot and is the median of all data below the median

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2 years ago

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Whitepunk [10]

Answer:

Step-by-step explanation:

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2 years ago

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Liquid A has a density of 0.7g/cm^3

TiliK225 [7]

$\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}$
ρ - density, m - mass, V - volume

Liquid A:
$\rho=0.7 \ \frac{g}{cm^3} \\
m=140 \ g \\
\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3$

Liquid B:
$\rho=1.6 \ \frac{g}{cm^3} \\
m=128 \ g \\
\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3$

Liquid C:
$m=140 \ g + 128 \ g=268 \ g \\
V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\
\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}$

The density of liquid C is approximately 0.96 g/cm³.

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3 years ago

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