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ad-work [718]
2 years ago
5

help plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz

plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz plz

Mathematics
2 answers:
ankoles [38]2 years ago
6 0

Answer:

hope you got it right

Step-by-step explanation:

Rudiy272 years ago
3 0

Answer:

Q. 4.

-> $3,333

Q. 5

-> $40,000

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</u>4   x<u>
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3 years ago
Ashley recently opened a store that sells only natural ingredients. She wants to advertise her products by distributing bags of
lesantik [10]
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3 years ago
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Does anyone know this?
Bumek [7]

Answer:

B

Step-by-step explanation:

Initial mean = 156, Changed mean = 163.92

So, mean increases. Only condition that satisfies this is B.

7 0
3 years ago
Help me please it’s question 33
shtirl [24]
I don’t see anything. What is the problem.
8 0
3 years ago
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Any REAL help on #16 above??? Can someone check my answer?
babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ±\frac{b}{a} (x - h)

Process

Find a, b

                a² = 9    

               a = 3

                b² = 5

              b = √5

              h = 0    and k = 1

Substitution

              y - 1 = ±\frac{√5}{3} (x - 0)

Equation 1

            y = \frac{\sqrt{5} }{3} x + 1

Equation 2

           y = - \frac{\sqrt{5} }{3} x + 1  

3 0
3 years ago
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