Answer: 
Step-by-step explanation:
The measure of the third unknown arc is
.
So, 
Answer:
24
Step-by-step explanation:
First do parenthesis:
3*(9+1)-6 -> 3*(10)-6
Then do multiplication:
3*(10)-6 -> (30)-6
Then complete it with subtraction:
(30)-6 -> (24)
So your answer would be 24!
PEMDAS= Parenthesis, Exponents, Multiplication, Division, Add, Subtract.
Answer:
Linear functions change at a constant rate per unit interval. An exponential function changes by a common ratio over equal intervals.
Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.