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jeka57 [31]
3 years ago
6

Three gallons of gasoline cost $3.36. How much does 5 gallon cost?

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0

Answer:

Step-by-step explanation:

5gal($3.36/3gal)=$5.60

aksik [14]3 years ago
4 0

Answer:

$5.68             i think

Step-by-step explanation:

I GOT THE POWER OF GOD AND ANIME ON MY SIDE

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If k=9 and x=5, find the value of the expression: <br> 2k - X<br><br> Please hurry
il63 [147K]

Answer:

\huge\boxed{13}

Step-by-step explanation:

= 2k - x

Given that k = 9, x = 5

= 2(9) - 5

= 18 - 5

= 13

\rule[225]{225}{2}

Hope his helped!

<h3>~AH1807</h3>
8 0
3 years ago
I need help with this ​
Zanzabum
3 + 3 + 3 + 3 + 5 + 5 = 22

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3 years ago
5. Don is planning to mount a television on a wall and wants to center it. The wall is 88 ¾ inches and he wants to have at least
irakobra [83]

Answer:

The largest it can be is 39.75

Step-by-step explanation:

88.75-(24.5*2)=39.75

88 3/4 - 24 1/2 - 24 1/2 = 39 3/4

5 0
4 years ago
One batch makes 15 lemon bars and Josh ate 2. If Claire ate twice as many as him, how many lemon bars would be left from the bat
Diano4ka-milaya [45]

Answer:

There are 9 lemon bars left from the batch.

Step-by-step explanation:

One batch = 15 lemon bars

Josh: ate 2 lemon bars

15 - 2 = 13

13 lemon bars remaining.

Claire: ate twice as many as Josh

Meaning: 2 × 2 = 4

13 - 4 = 9

9 lemon bars remaining.

There are 9 lemon bars left from the batch.

5 0
3 years ago
Which expressions are equivalent? Select two answers.
professor190 [17]

Answer:

<h2>A, C</h2>

Step-by-step explanation:

The distributive property:

<em>a(b + c) = ab + ac </em>or<em> a(b - c) = ab - ac</em>

<em></em>

A.\\\\\dfrac{1}{5}(x-50)=\dfrac{1}{5}x-\left(\dfrac{1}{5}\right)(50)=\dfrac{1}{5}x-\dfrac{50}{5}=\dfrac{1}{5}x-10\\\\B.\\\\-\dfrac{1}{3}(3x+18)=\left(-\dfrac{1}{3}\right)(3x)+\left(-\dfrac{1}{3}\right)(18)=-\dfrac{3}{3}x-\dfrac{18}{3}=-x-6\\\\-x-6\neq\dfrac{1}{3}x-6

C.\\\\\dfrac{1}{2}(x+16)=\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)(16)=\dfrac{1}{2}x+\dfrac{16}{2}=\dfrac{1}{2}x+8\\\\D.\\\\\dfrac{1}{8}(8x+8)=\left(\dfrac{1}{8}\right)(8x)+\left(\dfrac{1}{8}\right)(8)=\dfrac{8}{8}x+\dfrac{8}{8}=x+1\\\\x+1\neq\dfrac{1}{8}x+1\\\\E.\\\\-\dfrac{1}{4}(x+2)=-\dfrac{1}{4}x+\left(\dfrac{1}{4}\right)(2)=-\dfrac{1}{4}x+\dfrac{2\!\!\!\!\diagup^1}{4\!\!\!\!\!\diagup_2}=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\-\dfrac{1}{4}x+\dfrac{1}{2}\neq-\dfrac{1}{4}x+2

4 0
3 years ago
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