Given the table showing the distance Randy drove on one day of her vacation as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Time (h)&1&2&3&4&5\\[1ex] Distance (mi)&55&110&165&220&275 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATime%20%28h%29%261%262%263%264%265%5C%5C%5B1ex%5D%0ADistance%20%28mi%29%2655%26110%26165%26220%26275%0A%5Cend%7Btabular%7D)
The rate at which she travels is given by
If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by
distance = 55 x 6 = 330 miles.
Answer:
The answer is
<h2>4x + y - 6 = 0</h2>
Step-by-step explanation:
Equation of a line is y = mx + c
where m is the slope
c is the y intercept
4x + y + 1 = 0
y = - 4x - 1
Comparing with the above formula
Slope / m = - 4
Since the lines are parallel their slope are also the same
That's
Slope of the parallel line is also - 4
Equation of the line using point ( 1 , 2) is
y - 2 = -4(x - 1)
y - 2 = - 4x + 4
4x + y - 2 - 4
We have the final answer as
<h3>4x + y - 6 = 0</h3>
Hope this helps you
we are supposed to find
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.
The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.
In a parallelogram The opposite angles and opposite sides are always equal.
Hence the correct option is
The diagonals are congruent.
