Answer:
y ≤ −2x + 3
y ≤ x + 3
Step-by-step explanation:
they both share the slope of 3.
line a has a slope of -2
line b has a slope of 1
the sign ≤ means that the inequalities have a solid line and there below the line.
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Answer:

Step-by-step explanation:
Given expression:
2x + 5y = -10
The equation of a straight line is;
y = mx + c
y and x are the coordinates
m is the slope
c is the intercept
Now;
let us write the given expression in slope intercept format;
2x + 5y = -10
5y = -2x - 10
y =
- 2
So, the slope of the line is 
Answer:

- Multiply 5 by 5 to get your first parameter.

- Multiply 6 by 5 to get the denominator, or your second parameter.

- For the second fraction,
, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.


- The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.


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Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>
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<h3>What have we learned?</h3>
We learned how to efficiently make fractions' deominators match.
Questions related to this topic? Ask me in the comments box, please!
The equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
<h3>What is linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have two equation of the line:
y = -x -3 and
5y + 5x = -15
From the equation 5y + 5x = -15:
Divide by 5 on the above equation:
y + x = -3
or
y = -x -3
The two equations y = -x -3 represents the same line.
Thus, the equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
Learn more about the linear equation here:
brainly.com/question/11897796
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Answer:The crystal structures of five 6-mercaptopurine derivatives, viz. 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(3-methoxyphenyl)ethan-1-one (1), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-methoxyphenyl)ethan-1-one (2), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-chlorophenyl)ethan-1-one (3), C15H11ClN4O2S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-bromophenyl)ethan-1-one (4), C15H11BrN4O2S, and 1-(3-methoxyphenyl)-2-[(9H-purin-6-yl)sulfanyl]ethan-1-one (5), C14H12N4O2S. Compounds (2), (3) and (4) are isomorphous and accordingly their molecular and supramolecular structures are similar. An analysis of the dihedral angles between the purine and exocyclic phenyl rings show that the molecules of (1) and (5) are essentially planar but that in the case of the three isomorphous compounds (2), (3) and (4), these rings are twisted by a dihedral angle of approximately 38°. With the exception of (1) all molecules are linked by weak C—H⋯O hydrogen bonds in their crystals. There is π–π stacking in all compounds. A Cambridge Structural Database search revealed the existence of 11 deposited compounds containing the 1-phenyl-2-sulfanylethanone scaffold; of these, only eight have a cyclic ring as substituent, the majority of these being heterocycles.
Keywords: crystal structure, mercaptopurines, supramolecular structure
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Chemical context
Purines, purine nucleosides and their analogs, are nitrogen-containing heterocycles ubiquitous in nature and present in biological systems like man, plants and marine organisms (Legraverend, 2008 ▸). These types of heterocycles take part of the core structure of guanine and adenine in nucleic acids (DNA and RNA) being involved in diverse in vivo catabolic and anabolic metabolic pathways.
6-Mercaptopurine is a water insoluble purine analogue, which attracted attention due to its antitumor and immunosuppressive properties. The drug is used, among others, in the treatment of rheumathologic disorders, cancer and prevent
Step-by-step explanation: