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4 years ago

How to find lattice parameter from fourier transform cryoem?

1 answer:

6 0

The two-dimensional lattice repeat is identified and the frequencies that do not conform to this repeat are filtered from the Fourier transform of the image by setting ... Our approach does not need knowledge of the crystal lattice constants nor of the crystal orientation or location too bringing a good result.

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If C is the center of the circle, find the measure of KM

stiv31 [10]

Your answer is 160. Sorry about that answer above I laughed reading it hahaha.

6 0

4 years ago

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Will mark brainliest 20 pionts Show work

Rufina [12.5K]

Answer:

Part A) The percentage increase was $6.1\%$

Part B) Michael is financially better off this year than last year

Step-by-step explanation:

Part A)

we know that

Using proportion

Let

x-----> the percentage increase

$\frac{100\%}{33,000}=\frac{x\%}{35,000-33,000}\\ \\x=2,000*100\%/33,000\\ \\x=6.1\%$

Part B) Compare the percentage increase with the inflation

$6.1\%>5\%$

The percentage increase is greater than the inflation

therefore

Michael is financially better off this year than last year

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3 years ago

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Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.

kaheart [24]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------$

$\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
\\\\\\
\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
\\\\\\
7x^{2-1}y^{6-1}+2x^{1-1}y^{3-1}-10x^{1-1}y^{1-1}\implies 7xy^5+2y^2-10$

3 0

3 years ago

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Please help with the problem below

Andrej [43]

Answer:

ow that so hard

Step-by-step explanation:

wait let me see the answer i well search it

5 0

3 years ago

Which of the following transformations maps A to A’ in the figure below

LenKa [72]

Answer:

The answer is rotation 270° about the origin

Step-by-step explanation:

If (x , y) is a point in xy-coordinates

If the point rotate about the origin ⇒ (The positive direction is anti-clockwise)

1- 90°

Its image is (-y , x)

2- 180°

Its image is (-x , -y)

3- 270°

Its image is (y , -x)

If we assume A is (1 , 7)

1- ⇒ (-7 , 1) ⇒ rotation 90° about the origin

2- ⇒ (-1 , -7) ⇒ rotation 180° about the origin

3- ⇒ (7 , -1) ⇒ rotation 270° about the origin

∵ x-coordinate of point A small and +ve and y-coordinate large and +ve

∵ x-coordinate of point A' large and +ve and y-coordinate small and -ve

∴ The answer is rotation 270° about the origin

8 0

3 years ago

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