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Verdich [7]
3 years ago
11

I need an answer again for this question.

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

The area of these combined rectangles would be 40 square meters.

Step-by-step explanation:

First, let's partition this irregular shape into 3 rectangles. Let's begin with the first or larger rectangle. The formula of the area of a rectangle is length times width. So, we know the length is 10 meters, but we don't know the width. We can see the 5 meters measurements and subtract 6 meters with 5 meters to get us to 1 meter. We just found the width of the first rectangle; it is 1 meter. So, let us calculate 10 meters times 1 meter which equals 10 square meters. Keep this aside. Now, notice that the left and right rectangles are visually congruent. Let us focus on one rectangle, the left or right one; you choose. The length is 3 meters. Now, we have to deal with the width. 6 meters minus 1 meter is 5 meters. So do 3 meters times 5 meters which equals to 15 meters squared. Since we have two similar rectangles multiply that by two; so 15 square meters times two rectangles is 30 square meters. Now, add 30 square meters with the preliminary 10 meters and you get 40 square meters. Therefore, the area of the combined rectangles is 40 square meters. If this helps, please rank Brainliest. Thank you!

Sergeeva-Olga [200]3 years ago
6 0

Answer:

40

Step-by-step explanation:

The area of big rectangle is 60 because 10 multiple by 6 equal 60. And the area of small rectangle is 4 multiple by 5 equal 20.

So the answer is 60-20=40.

  Thank you

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7 0
3 years ago
Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

____

Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

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