Question

Combine the radicals 4V7 +3V28​

Answer 1

Answer:

Step-by-step explanation:

$4\sqrt{7}+3\sqrt{28}=4\sqrt{7}+3\sqrt{2*2*7}\\\\\\ =4\sqrt{7}+3*2\sqrt{7}\\\\\\= 4\sqrt{7}+6\sqrt{7}\\\\\\=(4+6)\sqrt{7}\\\\\\ =10\sqrt{7}$

Answer 2

Answer:

The answer is

$10 \sqrt{7}$

Step-by-step explanation:

To solve the radicals make sure that they both have the same radical

That's

$4 \sqrt{7} + 3 \sqrt{28}$

Simplify 3√28 in order to combine the radicals

We have

$3 \sqrt{4 \times 7} = 3 \times \sqrt{4} \times \sqrt{7}$

$= 3 \times 2 \times \sqrt{7}$

$= 6 \sqrt{7}$

So we now have

$4 \sqrt{7} + 6 \sqrt{7}$

Using the rules of surds

That's

$x \sqrt{a } + y \sqrt{a} = (x + y) \sqrt{a}$

Simplify the expression

We have

$4 \sqrt{7} + 6 \sqrt{7 } = (4 + 6) \sqrt{7}$

We have the final answer as

$10 \sqrt{7}$

Hope this helps you