Find the value of x such that sin (90-x) = cos 50
2 answers:
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Answer:
x = 4
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 1² = 9²
x² + 1 = 81 ( subtract 1 from both sides )
x² = 80 ( take square root of both sides )
x = =
=
×
= 4
We need to cut it up and find the areas of each
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)