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3 years ago

Find the value of x such that sin (90-x) = cos 50

Mathematics

2 answers:

olga_2 [115]3 years ago

8 0

Solution
sin (90-x)=sin (90-50)
90-x=40⇒x=90-40
x=50.

Arte-miy333 [17]3 years ago

3 0

Sin (90-x) = cos x

so x = 40

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2 years ago

S=a1/1-r

valentinak56 [21]

Answer:

Step-by-step explanation:

This is an infinite geometric series. This has a sum of $\frac{a}{1-r}$

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

First term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3$

Second term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}$

Let's see the common ratio: $\frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}$

Thus we have a = 3 and r = 1/4. Plugging into the formula of the infinite sum, we get:

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4 0

3 years ago

The sum of 4X and 2X is less than the difference of 5X and 13

eduard

Answer: 5x-13-(4x+2x)

Step-by-step explanation:

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3 years ago

A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location

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Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

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The test statistic for the Goodness of fit test is:

$\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}$

For k independent samples this test statistic follows a Chi-square distribution with degrees of freedom (k - 1).

The sample size in this case is, k = 5.

The degrees of freedom is, (k - 1) = 4.

The level of significance is, α = 0.01.

The critical value of the test is:

$\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277$

**Use the Chi-square table.

Thus, the critical value is 13.277.

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3 years ago

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Alekssandra [29.7K]

Answer:

2*5*7

Step-by-step explanation:

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3 years ago