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Novosadov [1.4K]
4 years ago
12

Suppose you have made the following hypothesis: Sharks are most common near coral reefs, because there are more fish there to ea

t.Suppose you observed 10 sharks on a coral reef in the Caribbean, and 15 sharks in the open ocean 50 miles away. Does this evidence support the hypothesis?
A. Yes, the evidence supports the hypothesis. B. No, the evidence contradicts the hypothesis. C. The evidence is not related to the hypothesis.
Physics
2 answers:
fiasKO [112]4 years ago
5 0

Answer:

A.

Explanation:

Brilliant_brown [7]4 years ago
3 0
I would say none of the options. This evidence does not support the hypothesis, but it doesn't contradict it, however it is related to the hypothesis. I guess what I'm trying to say is that the evidence isn't sufficient enough to make any definitive comments about the hypothesis. I don't think that you can just decide on whether to accept or reject your hypothesis based on observation alone and moreover, an observation that was made once. You need to make many observations, at certain points every day, in the same area of reef and the same area of open sea for a certain amount of time to gain a good amount of data (you could split up areas of reef and open sea on a particular coast into square meters or what ever unit you want and dedicate 3 days to each area you've split up) then you can perform a statistical test that suits the model of your data. I hope this helps in some way and I'm sorry it's so long. I couldn't think of a shorter way to say this.
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3 years ago
Can someone please help me answer 14 and 15??
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15.
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Answer:

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Explanation:

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2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after
sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

A(t)=A_oe^{\frac{-bt}{2m}}

or amplitude for unforce oscillation

\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}

or

\frac{6bt}{2m}=1

or

b=\frac{m}{3T}

Now, provided in the question Amplitude of the driven oscillation

A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}

the value of the maximum amplitude is obtained (k=m\omega_d^2)

thus,

A=\frac{F_{max}}{(b\omega_d}

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

0.075=\frac{nF}{((\frac{m}{3T})2\pi}

or

n = 1810

hence, there were 1810 people on the bridge

b)A=\frac{F_{max}}{(b\omega_d}

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

A=\frac{F_{max}}{(3b\omega_d}

or

A=\frac{1}{(3}A_o

or

A=\frac{1}{(3}0.075

or

A = 0.025 m = 25 mm

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3 years ago
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