Mathematically we know that the position is the integral of the velocity as a function of time, that is, the general formula for determining the position as a function of velocity would be given by
Here
represents the initial position, and the integral, the position with respect to the speed of the object within a certain time
Replacing and considering that there is no starting position,
Answer:
currrent will be halved
Explanation:
v = ir
v/r = i multiply both sides by 1/ 2
v / (2r) = 1/2 i
Left. Use right hand rule. Have hand wide open. Thumb points in direction of current.(which makes right angle with your index finger) Four fingers in direction of magnetic field and your palm should point in the direction of the force
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s
<h3>Data obtained from the question</h3>
The following data were obtained from the question given above:
- Initial velocity (u) = 11.1 Km/s
- Final velocity (v) = 11.7 Km/s
- Distance (s) = 1220 Km
- Time (t) =?
<h3>How to determine the time</h3>
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:
s = (u + v)t / 2
Cross multiply
(u + v)t = 2s
Divide both sides by (u + v)
t = 2s / (u + v)t
t = (2 × 1220) / (11.1 + 11.7)
t = 2440 / 22.8
t = 107 s
Thus, the time taken for the spaceship to change its speed is 107 s
Learn more about speed:
brainly.com/question/680492
Learn more about velocity:
brainly.com/question/3411682
#SPJ1
Answer:
range of movement is 1.49 mm
Explanation:
given data
focal length = 45 mm
distance = 1.4 m
distance from the lens = 35 mm
distance from infinity down = 1.4 m =
to find out
range of movement
solution
we will apply here lens equation that is
1/f = 1/p + 1/q
here f = 45 and p = infinity to 1400 mm
we find here image distance that is q
1/45 = 0 + 1/q ......1
q = 45 mm
and
1/45 = 1/1400 + 1/q ......2
q = 46.49
so range of movement
that is 46.49 - 45
range of movement is 1.49 mm
