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3 years ago

The speed of an electromagnetic wave is a constant, 3.0 × 10 8m/s. The wavelength of a wave is 0.6 meters.

Physics

2 answers:

antiseptic1488 [7]3 years ago

5 0

Explanation :

It is given that,

Speed of the wave, $v=3\times 10^8\ m/s$

Wavelength of the wave, $\lambda=0.6\ m$

We know that,

$v=f \lambda$

where

v is the speed of the wave

$\lambda$ is the wavelength of the wave

f is the frequency of the wave

$f=\dfrac{v}{\lambda}$

$f=\dfrac{3\times 10^8\ m/s}{0.6\ m}$

$f=500000000\ Hz$

$f=5.0\times 10^8\ Hz$

So, the correct option is (d).

Inessa [10]3 years ago

5 0

Answer:5.0 × 10 8Hz

Explanation:

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juie ran eight laps around her school's quarter mile track in 18 minutes. her average velocity was _______m/s

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Answer:

About 3m/s

Explanation:

If Julie ran eight quarter mile laps, then she ran a total of 1/4 * 8=2 miles. 2 miles is about 3220 meters, and 18 minutes is 1080 seconds, meaning that her average velocity was about 3m/s. Hope this helps!

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3 years ago

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An electron is released from rest at a distance of 0.570 m from a large insulating sheet of charge that has uniform surface char

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Explanation:

Formula to calculate the electric field of the sheet is as follows.

E = $\frac{\sigma}{2 \epsilon_{o}}$

And, expression for magnitude of force exerted on the electron is as follows.

F = Eq

So, work done by the force on electron is as follows.

W = Fs

where, s = distance of electron from its initial position

= (0.570 - 0.06) m

= 0.51 m

First, we will calculate the electric field as follows.

E = $\frac{\sigma}{2 \epsilon_{o}}$

= $\frac{4.60 \times 10^{-12}C/m^{2}}{2 \times 8.854 \times 10^{-12}C^{2}/N m^{2}}$

= 0.259 N/C

Now, force will be calculated as follows.

F = Eq

= $0.259 N/C \times 1.6 \times 10^{-19} C$

= $0.415 \times 10^{-19} N$

Now, work done will be as follows.

W = Fs

= $0.415 \times 10^{-19} N \times 0.51 m$

= $2.12 \times 10^{-20} J$

Thus, we can conclude that work done on the electron by the electric field of the sheet is $2.12 \times 10^{-20} J$ .

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4 years ago

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A 80 kg block starts from rest at the top of a 15m frictionless ramp. The block slides down the frictionless ramp onto a rough h

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Answer:

W(fric) = -12000 J

Explanation:

Given that

mass ,m= 80 kg

Initial speed ,u= 0 m/s

Height ,h= 15 m

Final speed ,v= 0 m/s

We know that

Work done by all the forces = Change in the kinetic energy

$W_{gravity}+W_{fric}=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2$

$W_{gravity}+W_{fric}=\dfrac{1}{2}m\times 0^2-\dfrac{1}{2}m\times 0^2$

$W_{gravity}+W_{fric}=0$

W(fric)= - m g h

W(fric) = - 80 x 10 x 15 ( g=10 m/s²)

W(fric) = -12000 J

negative sign indicates that force and displacement is in opposite direction.

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3 years ago

Black smokers are hot volcanic vents that emit smoke deep in the ocean floor. Many of them teem with exotic creatures, and some

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If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.

Calculation:

Step-1:

It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.

The gauge pressure at a particular depth of ocean water is calculated as:

$P=\rho g h$

Here $\rho$ is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.

Step-2:

Now we are substituting the values to calculate the pressure at the depth of 2452-m.

$\\\begin{aligned}\\P&=\rho gh\\&=1030 (\text{ kg/m}^3)\times 9.8 (\text{ m/s}^2)\times 2452 \text{ m}\\&=24.75\times 10^6 \text{ Pa}\times\frac{1 \text{ atm}}{10.1325 \times10^4 \text{ Pa}}\\&=224.268 \text{ atm}\\\end{aligned}\\$

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