Find the slope of the line passi g through the points (-4, -5) and (6, -5).

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

Answer:

slope = 0

Step-by-step explanation:

slope = (y2 -y1) / (x2 - x1) = (- 5 -(-5)) / ((6 -(-4)) = (-5+5)/10 = 0/10 = 0

Horizontal line.

You might be interested in

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago

Plz help will mark brainliest :)

shepuryov [24]

Answer:

an odd an even

Step-by-step explanation:

plz mark as brainliest. my first answer

3 0

3 years ago

Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

Aloiza [94]