the question is not very clear.......
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.</span>
Answer:
A. 2(8)+2(w)=26
B. 16+2w=26
Subtract 16 from both sides of the equation
2w=10
Divide both side by 2
The width is 5
Step-by-step explanation:
Gives an output of 1 I think
Answer:
61 + n = 82
Step-by-step explanation:
So the total number of candy is 82. This is the sum of each type of candy, i.e. 18 + 24 + 19 + n. So we have
18 + 24 + 19 + n = 82
61 + n = 82
( if we solve the equation we get n = 82 - 61 = 21)
Hope it helps and if it does please mark me brainliest;)
