All categories

3 years ago

Find the slope of the line passi g through the points (-4, -5) and (6, -5).

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

Answer:

slope = 0

Step-by-step explanation:

slope = (y2 -y1) / (x2 - x1) = (- 5 -(-5)) / ((6 -(-4)) = (-5+5)/10 = 0/10 = 0

Horizontal line.

You might be interested in

Find the distance between the two points rounding to the nearest tenth (if needed)

Ede4ka [16]

Answer:

6.3 units (nearest tenth)

Step-by-step explanation:

$\boxed{Distance \: between \: 2 \: points = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } }$

Using the formula above,

distance between (-8, 6) and (-6, 0)

$= \sqrt{ {[ - 8 - ( - 6)]}^{2} + {(6 - 0)}^{2} }$

$= \sqrt{ {( - 8 + 6)}^{2} + {(6 - 0)}^{2} }$

$= \sqrt{ {( - 2)}^{2} + 6^{2} }$

$= \sqrt{4 + 36}$

$= \sqrt{40}$

= 6.3 units (nearest tenth)

3 0

3 years ago

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 107°, a

Archy [21]

Answer: $105.19 \text{ square cm}$

Step-by-step explanation:

Since, by the SAS formula of finding the area of triangle,

The area of triangle, $A = \frac{1}{2}\times s_1\times s_2\times sin\theta$

Where, $s_1$ and $s_2$ are adjacent sides and $\theta$ is the included angle of these sides

Here, $s_1=22$ $s_2=10$

And, $\theta=107^{\circ}$

Thus, the area of the triangle ABC,

$A = \frac{1}{2}\times 22\times 10\times sin (107)^{\circ}$

$A = 110\times 0.95630475596$

$A = 105.193523156\approx 105.19\text { square cm}$

Therefore, Third Option is correct.

3 0

4 years ago

67×x[12+14]÷[22x×2]×2

marshall27 [118]

I started the problem, hope this helps

6 0

3 years ago

The sum of two numbers is 53. If their difference is 25 find both numbers.

timama [110]

Answer:

x=39

y=14

Step-by-step explanation:

x+y=53...(1)

x-y=25...(2)

(1)+(2): 2x==78

x=78/2

x=39

then

x+y=53

39+y=53

y=53-39

y=14

6 0

3 years ago

Select which equations are POLYNOMIALS and which are NOT POLYNOMIALS.

hammer [34]

In Polynomials all the exponents of x-variable must be positive integers, then polynomials are:
a) -x^5+7x-1/2x^2+9, the exponents of x's are: 5, 1, and 2
b) x^3-4x-3, the exponents of x's are: 3, and 1
f) x^4+x^3√7+2x^2-√3/2x+π, the exponents of x's are: 4, 3, 2, and 1

Not polynomials are:
c) 4 / x^2-4x+3 = 4x^(-2)-4x+3, the exponents of x's are -2, and 1
d) x^4+5/x^3-√x+8=x^4+5x^(-3)-x^(1/2)+8, the exponents of x's are 4, -3, and 1/2
e) |x|^2+4√x-2=|x|^2+4x^(1/2)-2, the exponents of x's are 2 and 1/2

6 0

3 years ago