If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?
2 answers:
The correct answer is: y =
Explanation:
The direct relation can be written as follows:
Now to remove the proportional sign, we use the constant of proportionality, let's say <em>k</em>, as follows:
When y = 6, x = 72, <em>k </em>will be:
Now we know the value of <em>k, </em>let's find the value of y when x = 8:
Hence the correct answer is: y =
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Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.
