write in slope intercept form an equation of the line that passes through the points (-15, -1) and (10,4)

1 answer:

4 0

Find the slope first
m=y2-y1/x2-x1
m=4+1/10+15
m=5/25 = 1/5
use point slope formula and plug in any points
y-y1=m(x-x1)
y-4=1/5(x-10)
y-4=1/5x-2
y=1/5x+2

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lys-0071 [83]

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$x^2 + 10x + y^2 -4y + -7 = 0$

Step-by-step explanation:

For any circle point with coordinate of center (a,b) and radius r

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Given

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thus, equation of circle can be written by substituting a and b with (-5 ,2) and r =6 as shown below

$(x-a)^2 + (y-b)^2 = r^2\\(x-(-5))^2 + (y-2)^2 = 6^2\\x^2 + 10x + 25 + y^2 -4y + 4 = 36\\=>x^2 + 10x + y^2 -4y + 29 = 36\\=>x^2 + 10x + y^2 -4y + 29 -36 = 36 -36\\=>x^2 + 10x + y^2 -4y + -7 = 0$