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kramer
3 years ago
8

student measuring how gasoline prices change records the cost of gas at 10 randomly selected stations in her hometown. One week​

later, she records the price again at the same 10 stations. Are these data paired or​ independent? Choose the correct answer below. Independent Paired
Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

We conclude that he used a paired two-sample t-test.

Step-by-step explanation:

We know that the student measuring how gasoline prices change records the cost of gas at 10 randomly selected stations in her hometown. One week​ later, she records the price again at the same 10 stations.

We conclude that he used a paired two-sample t-test.

Because at each gas station, the student measured the price of gas twice.

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Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

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3 years ago
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