Answer:
The Proof is given below.
Step-by-step explanation:
Given:
LN⊥KM,
KL≅ML
To Prove:
ΔKLN≅ΔMLN
Proof:
In Δ KLN and Δ MLN
KL ≅ ML ....……….{Given i.e Hypotenuse }
LN ≅ LN …………..{Reflexive Property}
∠ LNK ≅ ∠ LNM ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}
Δ KLN ≅ Δ MLN ….{By Hypotenuse Leg Theorem}
....Proved
Answer:
<h2>
{ 1 , 2 , 3 , 4 }</h2>
Explanation:
<h3>
<u>Domain</u><u> </u><u>and</u><u> </u><u>Range:</u></h3>
Let R be a relation from A to B. Then the set of first components or the set of elements of A are called domain and the set of second components or the set of elements of B are called the range.
Hope this helps...
Good luck on your assignment..
13/2 = 6.5
2/13 = 015
6.5-0.15 = 6.35
