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UkoKoshka [18]
3 years ago
11

Cuanto da √(1 ÷ 6^2 - 1 ÷ 10^2)

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>2</u><u>/</u><u>1</u><u>5</u>

Step-by-step explanation:

= \sqrt{ \frac{1}{ {6}^{2} }  -  \frac{1}{ {10}^{2} } }  \\ \\   =  \sqrt{ \frac{4}{225} }  \\  \\  =  \frac{ \sqrt{4} }{ \sqrt{225} }  \\  \\  =  \frac{2}{15}

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-3a - 4(a - 6) = 24 - 7a<br><br> Solve the equation <br><br> Thanks
Dominik [7]

-3a-4(a-6)=24-7a

-3a-4a+24=24-7a

-7a+24=24-7a

-7a+24=-7a+24

-7a+24-24=-7a+24-24

Simplify

Subtract the numbers

Subtract the numbers

−7a=-7a

Add 7a to both sides of the equation

-7a+7a =-7a+7a

Simplify

Combine like terms

Combine like terms

0=0

answer is 0=0

5 0
3 years ago
6.79x10 to the second power written in standard form
seraphim [82]
The answer would be 679 :)
6 0
3 years ago
PLEASE HELP ME. I NEED HELP​
scoundrel [369]

#3). $124.16 will be in amount of deposit

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3 0
4 years ago
Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (
Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0
3 years ago
Read 2 more answers
please please please please please please please please please please please please please please please please please help mey,
Ray Of Light [21]

Answer:

See below

Step-by-step explanation:

REMEMBER  sec = 1/cos ...so the left side is

[1/cos -1]   /  [1/cos  +1 ]    

  get common denominator for numerator and denominator

[ (1 -cos) /cos  ]  /  [ (1+cos) / cos ]    

 now flip the bottom fraction and multiply to get

[(1-cos/cos) ]  *  [ cos / (1+cos) ]    which simplifies to   ( the 'cos' term cancels)

(1-cos) / (1+cos)              done !

8 0
2 years ago
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