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3 years ago

Drag a statement or reason to each box to compete this proof.

Mathematics

1 answer:

alexandr402 [8]3 years ago

8 0

Answer:

The answers of the proof are the following:

2. Multiplication Property of Equality

3. x-2 = 8

4. Addition Property of Equality

5. x=10, Simplifying

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Find the missing side length BM. Round answer to the nearest tenth.

xenn [34]

Answer: BM = 21.4

Step-by-step explanation:

Considering the given triangle BMS, to determine angle BM, we would apply the sine rule. It is expressed as

m/SinM = s/SinS = b/SinB

Where m, s and b are the length of each side of the triangle and angle M, Angle S and angle B are the corresponding angles of the triangle.

From the information given,

Angle M = 102°

Angle B = 35°

Angle S = 180 - (102 + 35) = 43°

b = MS = 18

s = BM

Therefore

18/Sin 35 = BM/Sin 43

Cross multiplying, it becomes

BMSin35 = 18 × Sin 43

BM × 0.5736 = 18 × 0.6820

0.5736BM = 12.276

Dividing the left hand side and the right hand side of the equation by 0.5736, it becomes

0.5736BM/0.5736 = 12.276/0.5736

BM = 21.4

6 0

3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

Find the surface area of a cylinder with the following dimensions. Use 3. 14 for $. Round your answer to the nearest

kupik [55]

Answer:

Step-by-step explanation:

r=d/2=11.4/2=5.7

slant surface area=2πr*h=11.4×3.14×4.4=157.5024 cm^2

area of base and top=2(πr²)=2×3.14×(5.7)²=204.0372 cm²

total surface area=157.5024+204.0372=361.5396=361.5 sq. cm

7 0

2 years ago

(x-1)^2+(2-x)^2-3(x-5)*(x-5)

Natali5045456 [20]

Answer:

$-x^2+24x-70$

Step-by-step explanation:

$(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70$

Formula used =

$(a-b)^2 = a^2+ 2ab + b^2$

8 0

2 years ago

-4x + 12 = 8<br><br> Solve for x

jasenka [17]

Answer:

x=1

Step-by-step explanation:

1.Move the constant to the right

2. Calculate

3. Divide both sides

4 0

2 years ago