The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
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<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
Answer: Choice C)
g(x) = -|2x|
You get this answer by simply sticking a negative out front of the original function. In other words, g(x) = -f(x) or more technically, g(x) = -1*f(x).
The negative will flip every y coordinate from positive to negative (or vice versa)
You'll also use the idea that |2x| = 2|x|. The two can be pulled out since we can say |x*y| = |x|*|y|
So |2*x| = |2|*|x| = 2|x|
Step-by-step explanation:
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36 + 57 + 4 + 2 + 1 = 100 would do it.
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