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3 years ago

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Sara and Macki were doing a math activity together in class. They were told to review the two problem solutions shown below and

determine which of the two cards is correctly solved.
Which of the two cards is correctly solved?

1 answer:

IgorC [24]3 years ago

6 0

Answer:

I NEED THE ANSWER

Step-by-step explanation:

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Permutations and, combinations: problem type 2.

USPshnik [31]

Step-by-step explanation:

<u>Permutations</u>:

n<em>P</em><em> </em>r = n!/(n + r)!

<u>Combinations</u>:

<em>nCr</em> = n!/(n - r)!r!

c - combination

p - permutations

Since in both the problems they are looking for different groups, it is a combination problem. the order in which the people were selected in each group is not important, what is required are different groups.

<u>A.</u>

n = 51

r = 3

51<em>C</em><em> </em>3 = 51! / ((51 - 3) ×3!)

<em>51C</em><em>3</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>8</em><em>2</em><em>5</em><em> </em>groups

<u>OR:</u>

$c = \frac{51}{3} \times \frac{50}{2} \times 49$

$c = 20825$

<em><u>B</u></em><em><u>.</u></em>

$c = \frac{14}{4} \times \frac{13}{3} \times \frac{12}{2} \times 11$

$c = 1001$

5 0

2 years ago

What adds to equal 0 but multiplies to equal -4000?

alukav5142 [94]

-400 and 400 I think

5 0

3 years ago

Here is the right photo please help i need this before july 1st thank you

Reil [10]

Answer:

i hope this helps

Step-by-step explanation:

2 $x^{2}$ -16=0

+16 +16

2 $x^{2}$ =16

÷2 ÷2

$x^{2}$ = 8

$\sqrt{x^{2} }$ = $\sqrt{8}$

x= $\sqrt{8}$

-5 $x^{2}$ +9=0

-9 -9

-5 $x^{2}$ =-9

÷-5 ÷-5

$x^{2}$ =1.8

$\sqrt{x^{2} }$ = $\sqrt{1.8}$

x= $\sqrt{1.8}$

6 $x^{2}$ -15=27

+15 +15

6 $x^{2}$ =42

÷6 ÷6

$x^{2}$ =7

$\sqrt{x^{2} }$ = $\sqrt{7}$

x= $\sqrt{7}$

4 0

4 years ago

What is 250 percent of 50

timurjin [86]

Well if 50= 100 % then 250 percent =150. (if you meant 25% then 25)

5 0

3 years ago

PLEASEE Can someone help me with this and show the work

Orlov [11]

Answer:

The vertex form is: y = 3(x-2)^2 + 7 . The vertex is (2, 7)

Step-by-step explanation:

Write the function: y = 3x^2 - 12x + 11 in vertex form

The vertex form of a quadratic equation is:

y = m(x - a)^2 + b where (a,b) is the vertex

For y = 3x^2 - 12x + 11

Solve for m

y = 3(x^2 - 4x) + 11

Complete the Square:

y = 3(x^2 - 4x + 4) + 11 - 4

y = 3(x - 2)^2 + 7

The vertex then is (2, 7)

3 0

3 years ago

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