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nikklg [1K]
3 years ago
10

Consider the line y = 3x-2.

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

Step-by-step explanation: (a)  y = 3x - 8 (b)  3y + x - 16 = 0

(a) The line is y = 3x - 2

But the condition for parallelism is that for two lines to be parallel to each other, their gradients m must be equal, ie, m1 = m2

therefore, the gradient of the line above m1 = 3, m2 = 3

since the line passes through the coordinate of ( 4, 4 ),

we need to find the y intersect ( c ) by substitute for x, m and y in the equation below.

y = mx  + c

4 = 3 x 4 + c

4 = 12  + c

c = 4 - 12

c = -8

Therefore, substitute for  c in the equation of a line above to get the second equation

y = mx + c

y = 3x - 8

(b) Condition for perpendicularity of two line is that  the product of their gradients must be( -1 )

ie, m1m2 = -1

Now from the equation above, y = 3x - 2, m1 = 3 and m2 = -1/3

to get the value of c, we substitute for  x, y and m into the equation

y = mx + c

4 = -1/3 x 4 = c

4 = -4/3 + c

multiply through by 3 to make it a linear equation

12 = -4 + 3c

12 + 4 = 3c

16 = 3c

c = 16/3

now put c = 16/3 into the equation , y=mx + c

y = -x/3  + 16/3

multiply through by 3

3y = -x + 16

3y + x - 16 =0

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