Answer:
The solutions listed from the smallest to the greatest are:
x:
![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
y: -1 1 -1 1
Step-by-step explanation:
The slope of the tangent line at a point of the curve is:
![m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B%5Cfrac%7Bdy%7D%7Bdt%7D%20%7D%7B%5Cfrac%7Bdx%7D%7Bdt%7D%20%7D)
![m = -\frac{\cos 2\theta}{\sin \theta}](https://tex.z-dn.net/?f=m%20%3D%20-%5Cfrac%7B%5Ccos%202%5Ctheta%7D%7B%5Csin%20%5Ctheta%7D)
The tangent line is horizontal when
. Then:
![\cos 2\theta = 0](https://tex.z-dn.net/?f=%5Ccos%202%5Ctheta%20%3D%200)
![2\theta = \cos^{-1}0](https://tex.z-dn.net/?f=2%5Ctheta%20%3D%20%5Ccos%5E%7B-1%7D0)
![\theta = \frac{1}{2}\cdot \cos^{-1} 0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Ccos%5E%7B-1%7D%200)
, for all ![i \in \mathbb{N}_{O}](https://tex.z-dn.net/?f=i%20%5Cin%20%5Cmathbb%7BN%7D_%7BO%7D)
, for all ![i \in \mathbb{N}_{O}](https://tex.z-dn.net/?f=i%20%5Cin%20%5Cmathbb%7BN%7D_%7BO%7D)
The first four solutions are:
x:
![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
y: 1 -1 1 -1
The solutions listed from the smallest to the greatest are:
x:
![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
y: -1 1 -1 1
Answer is C but if its on grad point your answer is 0.5(2)^x
B.90 because 90 degrees is above the original angel
S = 60W + 650 <== ur equation
after 18 weeks...so sub in 18 for W
S = 60(18) + 650
S = 1080 + 650
S = 1730 <==
Answer:
On first visit, weight =550 g
Weight gained on second visit= 350 g
Weight gained on third visit= 300 g
Present weight=550+350+300= 1200
Weight gained=1200-550=650
Percentage of weight increased
-------->650/550 × 100 = 118.18\%
So the kitten gained 118% weigh
Step-by-step explanation: