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liraira [26]
3 years ago
9

I need help with 4 pls help

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

so, to explain:

you first have to convert.

1) you make the denominators the same. however, when multiplying to make the denominators the same, you have to multiply the numerator as well.

1 \frac{1}{3} ( \times 4) =1 \frac{4}{12}

2 \frac{3}{4} ( \times 3) = 2 \frac{9}{12}

2) since the problems asks for total cups of sugar, (total meaning you have to add) we add.

1+2= 3 4+9= 13

the denominator stays the same for both fractions through the entire problem after this.

the fraction then looks like

3 \frac{13}{12}

3) since the numerator is larger than the denominator, you subtract the number at the denominator from the one on the numerator. 13-12= 1.

4) since you only had to subtract once before the numerator became smaller then the denominator, 13 divides into 12 once. so, you add one to the whole number.

5) this would make the answer to the question,

4 \frac{1}{12}

6) please read the instructions, it took a while to make and I did it so a random person idk could understand a topic. use it to inderstand this fully. if you need anymore help, just follow me so you can ask any time.

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Assuming we want to factor the formula to (x+3)(x+3), you want to have a +9 where there is a -4 now. So you must add 13.


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lana66690 [7]

Regarding the inequality defined by −8(x − 1) ≥ 88, we have that:

A. The solution is given by: x < -4.

B. On the number line, the solution set is composed by x = -10 and the values to the left of it.

C. Two possible solutions are x = -11 and x = -12.

<h3>Solving the inequality</h3>

The inequality is defined by:

−8(x − 1) ≥ 88

It is solved similarly to an equality, applying the distributive property and isolating the variable x, finding a range of values of x which are the solution to the inequality, as follows:

−8(x − 1) ≥ 88

8(x - 1) ≤ -88 (multiplication by -1 changes the inequality signal)

x - 1 ≤ -11 (simplify both sides of the inequality by 8).

x ≤ -10.

This the solution set is composed by the value of x = -10 and the values to the left of it, and two possible solutions are x = -11 and x = -12, which are numbers that are less than, that is, to the left of x = -10.

Learn more about inequalities at brainly.com/question/25275758

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\vec R(s)=\langle2+s,-8+3s,-12+4s\rangle

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\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=\langle6,3,4\rangle

\dfrac{\mathrm d\vec R(s)}{\mathrm ds}=\langle1,3,4\rangle

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\langle6,3,4\rangle\times\langle1,3,4\rangle=\langle0,-20,15\rangle

The two given lines intersect when \vec r(t)=\vec R(s):

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The line perpendicular to both of the given lines through the origin is obtained by scaling the normal vector found earlier by \tau\in\Bbb R; translate this line by adding the vector \langle6,4,4\rangle to get the line we want,

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\boxed{\vec\rho(\tau)=\langle6,4-20\tau,4+15\tau\rangle}

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