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Lorico [155]
3 years ago
11

A cinema has three screens . last saturday there were 500 visitor . 40% went to screen 1 . 25% went to screen 2. The rest went t

o screen 3. Workout how many visitor attended each screen?
Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

Screen 1: 200, Screen 2: 125 , Screen 3: 175

Step-by-step explanation:

Screen 1

Multiply 40% and 500

Convert 40% to a decimal

40/100=0.40

500*0.40

200

Screen 2

Multiply 25% and 500

Convert 25% to a decimal

25/100=0.25

500*0.25

125

Screen 3

Subtract the amount of people that went to screens 1 and 2 from the total

500-200-125

175

So, Screen 1 had 200 visitors, 2 had 125 and 3 had 175

Hope this helps! :)

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Given:quadrillateral ABCD inscribed in a circle
son4ous [18]

Answer:

Step-by-step explanation:

Given: quadrilateral ABCD inscribed in a circle

To Prove:

1. ∠A and ∠C are supplementary.

2. ∠B and ∠D are supplementary.

Construction : Join AC and BD.

Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,

∠1=∠2-----(1)

∠3=∠4-----(2)

∠5=∠6-------(3)

∠7=∠8------(4)

Also, sum of angles of quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°

→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4

→→→2∠1+2∠4+2∠6+2∠8=360°

→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,

→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)

As, ∠A+∠B+∠C+∠D=360°

∠A+∠C+180°=360°

∠A+∠C=360°-180°------Using A

∠A+∠C=180°

Hence proved.

credit: someone else

5 0
3 years ago
Which unit rate corresponds to the proportional relationship shown in the graph?
Evgen [1.6K]

Answer:

1.5 cm/s​

Step-by-step explanation:

The unit rate is the same as the slope.

To find the slope, we use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Using our points, we have

m = (9-0)/(6-0) = 9/6 = 3/2 = 1.5 cm/s

6 0
3 years ago
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The answers is what I got but it said it was wrong. can anyone hhelp find the right answer?​
klio [65]

Answer:

but its right

Step-by-step explanation:

5 0
2 years ago
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Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic
pishuonlain [190]

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

7 0
3 years ago
Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The
mr_godi [17]
F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x =  2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
8 0
3 years ago
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