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Sveta_85 [38]
3 years ago
12

Solve for x. -3x + 4 = -2x + 0 A 4 B 0.25 С -4 D -0.25

Mathematics
2 answers:
aalyn [17]3 years ago
7 0

Answer:

4

Step-by-step explanation:

-3x+2x=0-4

-x=-4

Divide both sides with a minus to get positive.

Therefore, x is 4.

Tresset [83]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3x+4=−2x+0

−3x+4=(−2x)+(0)(Combine Like Terms)

−3x+4=−2x

−3x+4=−2x

Step 2: Add 2x to both sides.

−3x+4+2x=−2x+2x

−x+4=0

Step 3: Subtract 4 from both sides.

−x+4−4=0−4

−x=−4

Step 4: Divide both sides by -1.

−x

−1

=

−4

−1

x=4

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3 years ago
The table below shows the numbers of tickets sold at a movie theater on Friday.
sleet_krkn [62]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday  

= Sum of ( Adult + Children's ) tickets  = 1,678  + 976 = 2,654 ....  (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold =   2 times as many as the number of adult tickets sold

on Friday

=  1,678 x 2  = 3,356

Children's Tickets sold = 3 times as many as the number of children's

tickets sold on Friday.

=  976  x 3 = 2, 928

So, the total number of tickets sold on Saturday  

= Sum of ( Adult + Children's ) tickets  = 3,356 + 2,928 = 6, 284 ....  (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

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3 years ago
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1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



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